2(x^1y+5x^2+3xy)=

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Solution for 2(x^1y+5x^2+3xy)= equation:


Simplifying
2(xy + 5x2 + 3xy) = 0

Reorder the terms:
2(xy + 3xy + 5x2) = 0

Combine like terms: xy + 3xy = 4xy
2(4xy + 5x2) = 0
(4xy * 2 + 5x2 * 2) = 0
(8xy + 10x2) = 0

Solving
8xy + 10x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.
2x(4y + 5x) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(4y + 5x)' equal to zero and attempt to solve: Simplifying 4y + 5x = 0 Reorder the terms: 5x + 4y = 0 Solving 5x + 4y = 0 Move all terms containing x to the left, all other terms to the right. Add '-4y' to each side of the equation. 5x + 4y + -4y = 0 + -4y Combine like terms: 4y + -4y = 0 5x + 0 = 0 + -4y 5x = 0 + -4y Remove the zero: 5x = -4y Divide each side by '5'. x = -0.8y Simplifying x = -0.8y

Solution

x = {0, -0.8y}

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